Given, x2+ax+b=0 For district now zero roots D>0 ⇒‌‌a2−4b>0 Now, x2+ax+b =(x+‌
a
2
)2+(b−‌
a2
4
) =(x+‌
a
2
)2−(a2−‌
4b
4
) We know, sum of roots a+b=−a ⇒‌‌2a+b=0 .....(i) Product of roots a×b=b ⇒‌‌b(a−1)=0 ⇒‌‌a=1,b≠0 From Eq. (i). 2a+b=0 2(1)+b=0 b=−2 Now, (x+‌