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KEAM 2017 Math Paper
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© examsnet.com
Question : 61
Total: 120
If
(
x
+
y
x
−
y
2
x
+
z
x
+
z
)
=
(
0
0
1
1
)
,
then the values of x,y and z are respectively
0, 0, 1
1, 1, 0
-1, 0, 0
0, 0, 0
1, 1, 1
Validate
Solution:
We have,
[
x
+
y
x
−
y
2
x
+
z
x
+
z
]
=
[
0
0
1
1
]
⇒
x
+
y
=
0
,
x
−
y
=
0
,
2
x
+
z
=
1
,
x
+
z
=
1
On solving above equations, we get
x
=
y
=
0
,
z
=
1
© examsnet.com
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