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KEAM 2017 Math Paper
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© examsnet.com
Question : 69
Total: 120
Let x = 2 be a root of
y
=
4
x
2
–
14
x
+
q
=
0.
Then y is equal to
(x – 2) (4x – 6)
(x – 2) (4x + 6)
(x – 2) (-4x – 6)
(x – 2) (-4x + 6)
(x – 2) (4x + 3)
Validate
Solution:
We have,
y
=
4
x
2
−
14
x
+
q
=
0
since,
x
=
2
is the root
∴
4
(
2
)
2
−
14
(
2
)
+
q
=
0
⇒
16
−
28
+
q
=
0
⇒
q
=
12
∴
y
=
4
x
2
−
14
x
+
12
=
4
x
−
8
x
−
6
x
+
12
=
4
x
(
x
−
2
)
−
6
(
x
−
2
)
=
(
x
−
2
)
(
4
x
−
6
)
© examsnet.com
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