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KEAM 2017 Math Paper
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© examsnet.com
Question : 9
Total: 120
The equation of the line passing through (– 3, 5) and perpendicular to the line through the points (1, 0) and (– 4, 1) is
5x + y + 10 = 0
5x – y + 20 = 0
5x – y – 10 = 0
5x + y + 20 = 0
5y – x – 10 = 0
Validate
Solution:
E slope of the line passing through
(
1
,
0
)
and
(
−
4
,
1
)
=
1
−
0
−
4
−
1
=
−
1
5
∴
Slope of line perpendicular to the above line
=
−
1
(
−
1
5
)
=
5
∴
Equation of required line is given by
y
−
5
=
5
(
x
−
(
−
3
)
)
⇒
y
−
5
=
5
(
x
+
3
)
⇒
y
−
5
=
5
x
+
15
⇒
5
x
−
y
+
20
=
0
© examsnet.com
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