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KEAM 2017 Physics and Chemistry Paper
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© examsnet.com
Question : 34
Total: 120
A standing wave propagating with velocity 300 m/s in an open pipe of length 4 m has four nodes. The frequency of the wave is
75 Hz
100 Hz
150 Hz
300 Hz
600 Hz
Validate
Solution:
Nodes are produced in the open pipe as shown in figure.
So,
2
λ
=
4
λ
=
4
2
=
2
m
From wave equation,
v
=
n
λ
n
=
v
λ
=
300
2
=
150
H
z
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