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KEAM 2018 Math Paper
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© examsnet.com
Question : 12
Total: 120
The focus of the parabola
(
y
+
1
)
2
=
−
8
(
x
+
2
)
is
(
−
4
,
−
1
)
(
−
1
,
−
4
)
(
1
,
4
)
(
4
,
1
)
(
−
1
,
4
)
Validate
Solution:
Given,
(
y
+
1
)
2
=
−
8
(
x
+
2
)
Y
2
=
−
8
X
....(i)
Here,
Y
=
y
+
1
,
X
=
(
x
+
2
)
Vertices
(
X
=
0
,
Y
=
0
)
=
(
−
2
,
−
1
)
Comparing Eq. (i) from
y
2
=
4
a
x
4
a
=
−
8
a
=
−
2
Focus
=
(
−
2
−
2
,
−
1
)
=
(
−
4
,
−
1
)
© examsnet.com
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