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KEAM 2018 Math Paper
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© examsnet.com
Question : 34
Total: 120
If the sides of a triangle are 4, 5 and 6 cms. Then the area of triangle is ........sq.cms.
π
4
π
4
√
7
4
15
4
15
√
7
15
4
√
7
Validate
Solution:
Given, triangle of sides
=
a
,
b
,
c
=
4
,
5
,
6
c
m
∴
S
=
a
+
b
+
c
2
=
4
+
5
+
6
2
=
15
2
Then, area of triangle
=
√
S
(
S
−
a
)
(
S
−
b
)
(
S
−
c
)
=
√
15
2
(
15
2
−
4
)
(
15
2
−
5
)
(
15
2
−
6
)
=
√
15
2
⋅
(
7
2
)
(
5
2
)
(
3
2
)
=
15
4
√
7
© examsnet.com
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