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KEAM 2018 Math Paper
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© examsnet.com
Question : 93
Total: 120
If f is differentiable at x = 1 and
lim
h
→
0
1
h
f
(
1
+
h
)
=
5
,
then
f
′
(
1
)
=
0
1
3
4
5
Validate
Solution:
f
′
(
1
)
=
lim
h
→
0
f
(
1
+
h
)
−
f
(
1
)
h
;
function is differentiable.
f
(
1
)
=
0
and
lim
h
→
0
f
(
1
+
h
)
h
=
5
;
Given function is continuous.
Hencc,
f
′
(
1
)
=
lim
h
→
0
f
(
1
+
h
)
h
=
5
© examsnet.com
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