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KEAM 2018 Math Paper
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© examsnet.com
Question : 99
Total: 120
The area bounded by
y
=
s
i
n
2
x
,
x
=
x
2
and
x
=
π
is
π
2
π
4
π
8
π
16
2
π
Validate
Solution:
Required area
=
∫
π
2
π
sin
2
x
d
x
=
∫
π
2
π
[
1
−
cos
2
x
2
]
d
x
=
1
2
[
x
−
sin
2
x
2
]
π
2
π
=
1
2
[
(
π
−
0
)
−
(
π
2
−
0
)
]
=
1
2
[
π
2
]
=
π
4
© examsnet.com
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