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KEAM 2018 Physics and Chemistry Paper
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© examsnet.com
Question : 20
Total: 120
The maximum transverse velocity and maximum transverse acceleration of a harmonic wave in a one-dimensional string are 1
m
s
−
1
and 1
m
s
−
2
respectively. The phase velocity if the wave is 1
m
s
−
1
.
The waveform is
s
i
n
(
x
−
t
)
s
i
n
(
2
x
−
t
)
s
i
n
(
x
−
2
t
)
s
i
n
(
x
2
−
t
)
s
i
n
(
x
−
t
2
)
Validate
Solution:
∵
Wave equation,
y
=
A
0
sin
(
k
x
−
ω
t
)
.....(i)
where,
k
=
angular wave number
=
2
π
λ
A
0
=
amplitude
∵
v
max
=
a
ω
∴
ω
=
1
( ∵ given that
v
max
=
1
m
s
,
a
=
1
m
s
2
)
∵
k
=
1
(given)
∴
From Eq. (i),
y
=
sin
(
x
−
t
)
© examsnet.com
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