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KEAM 2018 Physics and Chemistry Paper
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© examsnet.com
Question : 41
Total: 120
Two identical systems, with heat capacity at constant volume that varies as
C
v
=
b
T
3
(where b is a constant) are thermally isolated. Initially, one system is at a temperature 100 K and the other is at 200 K. The systems are then brought nto thermal contact and the combined system is allowed to reach thermal equilibrium. The final temperature (in K) of the combined system will be
171
141
150
180
125
Validate
Solution:
(
a
)
Energy given by a system
=
Energy taken by another system
d
Q
1
=
d
Q
2
⇒
=
T
∫
100
m
c
v
d
T
=
−
T
∫
200
m
c
v
d
T
⇒
T
∫
100
b
T
3
d
T
=
−
T
∫
200
b
T
3
d
T
⇒
(
T
4
)
10
T
=
−
(
T
4
)
200
T
⇒
T
4
−
100
4
=
−
(
T
4
−
200
4
)
⇒
2
T
4
=
17
×
10
8
⇒
T
=
171
K
© examsnet.com
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