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KEAM 2019 Math Paper
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© examsnet.com
Question : 34
Total: 121
If
3
49
(
x
+
i
y
)
=
(
3
2
+
√
3
i
2
)
100
and
x
=
k
y
, then
k
is
−
√
3
−
1
√
3
−
1
3
3
√
3
Validate
Solution:
3
49
(
x
+
i
y
)
=
(
3
2
+
√
3
i
2
)
100
=
[
i
√
3
(
1
−
i
√
3
2
)
]
100
⇒
3
49
(
x
+
i
y
)
=
i
100
⋅
3
50
⋅
(
−
ω
)
100
⇒
3
49
(
x
+
i
y
)
=
3
50
⋅
ω
=
3
50
(
−
1
2
+
i
√
3
2
)
∴
x
+
i
y
=
−
3
2
+
3
√
3
i
2
⇒
x
=
−
1
√
3
y
∴
k
=
−
1
√
3
© examsnet.com
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