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KEAM 2019 Math Paper
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© examsnet.com
Question : 57
Total: 121
The coordinates of a point on the line
x
+
1
2
=
y
−
1
3
=
z
−
1
1
at a distance of
√
56
units from the point
(
1
,
2
,
0
)
are
(
5
,
−
5
,
1
)
(
3
,
7
,
3
)
(
−
5
,
5
,
1
)
(
5
,
5
,
1
)
(
−
3
,
−
7
,
−
3
)
Validate
Solution:
The coordinates of any point on the given line are :
(
2
r
−
1
,
3
r
+
1
,
r
+
1
)
The distance of this point from
(
1
,
2
,
0
)
is
√
56
⇒
(
2
r
)
2
+
(
3
r
)
2
+
(
r
)
2
=
(
√
56
)
2
⇒
14
r
2
=
56
⇒
r
=
±
2
Hence, coordinates of the requiredpoint is:
(
3
,
7
,
3
)
or
(
−
5
,
−
5
,
−
1
)
© examsnet.com
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