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KEAM 2019 Math Paper
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© examsnet.com
Question : 6
Total: 121
If
|
1
a
a
2
1
x
x
2
b
2
a
b
a
2
|
=
0
then,
x
=
a
b
a
b
,
a
b
a
,
a
0
Validate
Solution:
We have,
|
1
a
a
2
1
x
x
2
b
2
a
b
a
2
|
Applying,
R
3
→
R
3
−
R
1
and
R
2
→
R
2
−
R
1
we get,
(
x
−
a
)
(
b
−
1
)
|
1
a
a
2
0
1
x
+
a
b
+
1
a
0
|
=
0
Which gives
x
=
a
b
,
a
© examsnet.com
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