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KEAM 2019 Physics and Chemistry Paper
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© examsnet.com
Question : 13
Total: 120
A wave along a string has the following equation y = 0.05 sin (28t - 2.Ox) m (where t is in seconds and x is in meters). What are the amplitude, frequency and wavelength of the wave?
amplitude = 0.05 m, frequency = 4.456 Hz and wavelength =3.518 m
amplitude = 0.05 m, frequency = 28 Hz and wavelength =2.0 m
amplitude = 5.0 m, frequency = 4.456 Hz and wavelength =3.518 m
amplitude = 0.05 m, frequency = 2.0 Hz and wavelength = 28 m
amplitude = 0.05 m, frequency = 3.456 Hz and wavelength =4.518 m
Validate
Solution:
Given the equation of wave along string
y
=
0.05
sin
(
28
t
−
1.78
x
)
.....(i)
The general equation of a wave is given as
y
=
A
sin
(
ω
t
−
k
x
)
......(ii)
Now, comparing Eqs. (i) and (ii), we get
Amplitude,
A
=
0.05
m
,
k
=
1.78
and
ω
=
28
⇒
Frequency,
f
=
ω
2
π
=
28
2
π
=
4.456
H
z
and wavelength,
λ
=
2
π
k
=
2
π
1.78
=
3.529
m
© examsnet.com
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