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KEAM 2020 Math Paper
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© examsnet.com
Question : 55
Total: 120
A circle with centre at (3,6) passes through (-1,1) . Its equation is
x
2
+
y
2
−
6
x
−
12
y
+
3
=
0
x
2
+
y
2
+
6
x
−
10
y
+
3
=
0
x
2
+
y
2
−
3
x
−
6
y
+
1
=
0
x
2
+
y
2
+
5
x
+
9
y
+
5
=
0
x
2
+
y
2
−
6
x
−
12
y
+
4
=
0
Validate
Solution:
r
2
=
4
2
+
5
2
=
41
(
x
−
3
)
2
+
(
y
−
6
)
2
=
41
x
2
+
y
2
−
6
x
−
12
y
+
4
=
0
© examsnet.com
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