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KEAM 2020 Math Paper
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© examsnet.com
Question : 97
Total: 120
If
y
=
2
+
√
u
and
u
=
x
3
+
1
,
then
d
y
d
x
=
x
2
2
√
x
3
+
1
3
x
2
√
x
3
+
1
3
x
2
2
√
x
3
+
1
3
x
2
√
x
3
+
1
x
2
√
x
3
+
1
Validate
Solution:
y
=
2
+
√
u
d
y
d
x
=
1
2
√
u
×
d
u
d
x
,
d
y
d
x
=
3
x
2
=
3
x
2
2
√
x
3
+
1
© examsnet.com
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