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KEAM 2021 Math Solved Paper
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© examsnet.com
Question : 25
Total: 120
The foci of a hyperbola are
(
8
,
3
)
and
(
0
,
3
)
and eccentricity is
4
3
. Then the length of the transverse axis is
32
3
4
8
8
3
6
Validate
Solution:
Distance between foci
(
8
,
3
)
and
(
0
,
3
)
is
√
(
0
−
8
)
2
+
(
3
−
3
)
2
=
8
⇒
2
a
e
=
8
⇒
a
e
=
4
⇒
a
(
4
3
)
=
4
(
given,
e
=
4
3
)
⇒
a
=
3
∴
Length of transverse axis
=
2
a
=
2
×
3
=
6
© examsnet.com
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