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KEAM 2021 Physics and Chemistry Solved Paper
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© examsnet.com
Question : 70
Total: 120
If the ratio of the acceleration due to gravity on the surface of earth to that on the surface of the moon is
6
:
1
, then the ratio of the periods of a simple pendulum on their surfaces is
1
:
1
1
:
6
1
:
3
1
:
√
6
1
:
√
3
Validate
Solution:
Given,
acceleration due to gravity on earth,
g
e
acceleration due to gravity on moon,
g
m
=
6
1
Time period of simple pendulum is given by
T
=
2
π
√
l
g
⇒
T
∝
√
1
g
⇒
T
e
T
m
=
√
g
m
g
e
where,
T
e
and
T
m
is the time period on the surface of earth and moon, respectively.
Using Eq. (i), we get
T
e
T
m
=
√
1
6
=
1
√
6
© examsnet.com
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