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KEAM 2022 Math Solved Paper

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Question : 58

Total: 120

The value of [‌

(1−i)(2−i)(3−i)

]50 is equal to

(‌
1
2
)25
(‌
1
2
)50
−(‌
1
2
)25
−(‌
1
2
)50
(‌
1
10
)50

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