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Kerala KEAM 10 June 2024 Solved Paper
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Question : 51 of 75
Marks:
+1
,
-0
The molar enthalpy of vaporization of water at 1 bar and
10
0
∘
100^{\circ}
10
0
∘
C is
41
k
J
m
o
l
−
1
41 kJ mol^{-1}
41
k
J
m
o
l
−
1
. What is the internal energy change, when 1 mol of water is vaporized at 1 bar pressure and
10
0
∘
100^{\circ}
10
0
∘
C? Assume water vapor as a perfect gas. (
R
=
8.3
J
K
−
1
m
o
l
−
1
R = 8.3 J K^{-1} mol^{-1}
R
=
8.3
J
K
−
1
m
o
l
−
1
)
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37.9
Â
k
J
 
m
o
l
−
1
37.9\ \mathrm{kJ\,mol^{-1}}
37.9
Â
kJ
mo
l
−
1
44.1
44.1
44.1
kJ mol
−
1
^{-1}
−
1
34.7
34.7
34.7
kJ mol
−
1
^{-1}
−
1
47.9
47.9
47.9
kJ
m
o
l
−
1
\mathrm{mol}^{-1}
mol
−
1
34.9
34.9
34.9
kJ
m
o
l
−
1
\mathrm{mol}^{-1}
mol
−
1
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