We are given the differential equation: cosydy=dxWe can separate the variables y and x as follows: cosydy=dx⇒∫cosydy=∫dxThe integral of cosy1 is secy, and the integral of dx is x. Thus, we have: secy=x+CNow, to solve for y, take the logarithm of both sides: log∣secy+tany∣=x+CThus, the correct answer is option (E): log∣secy+tany∣=x+CThus, the correct answer is option (E). Quick Tip: For integrals involving trigonometric functions like secy, use the identity sec2y−tan2y=1 to simplify the expression if necessary. Also, remember to apply logarithms when dealing with functions of the form secy+tany.