2‌sin‌α+3‌cos‌β=3√2 ....(1) 3‌sin‌β+2‌cos‌α=1....(2) sum of squares of equation (1) and (2) 4+9+12‌sin(α+β)=19 sin(α+β)=
1
2
⇒α+β=150°‌or‌30° If α+β=30°⇒β=30−α put in equation (1) and (2) we get 7‌sin‌α+3√3‌cos‌α=6√2 7‌cos‌α−3√3‌sin‌α=2 cos‌α=