From statement I The time taken to cover 40 km is not known. From statement II If PQ = xkm then the distance covered by the troubled engine = (x- 40) km Usual speed = 240​ = 20 kmph Usual time = (20x​) hours ∴ 2 hours + 5x−40​−20x​ = 6040​ = 32​ ⇒ 20x​ = 5x−40​ = 2 - 32​ ⇒ 20x−4x+160​ = 34​ ⇒ (-3x+ 160)3 = 80 ⇒ 9x = 480 - 80 = 400 ⇒ x = 9400​ = 44 91​ km