Concept:Solve the system of linear equations to find the intersection point, then determine its quadrant.Explanation:Given lines: 3x+2y=6 and 3x−y=12.Subtract the second equation from the first: (3x+2y)−(3x−y)=6−12.This gives 3y=−6, so y=−2.Substitute y=−2 into 3x−y=12: 3x−(−2)=12 → 3x+2=12 → 3x=10 → x=310​.The intersection point is (310​,−2).x>0, y<0: this lies in the fourth quadrant.Answer:D. 4th quadrant