If m+ n= (m+n) then m is

Correct Answer is : 1n−1\; 1/n-1n−11

Correct Answer is : 1n−1\; 1/n-1n−11

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Logarithms

Question : 10 of 85

Marks: +1, -0

\log m+\log n=\log (m+n)

m

Solution:

Concept:

Use the logarithm product rule

\log a + \log b = \log(ab)

to combine the two logs.

Explanation:

Given:

\log m + \log n = \log(m+n)

Apply the product rule:

\log(mn) = \log(m+n)

Since the bases are the same, equate the arguments:

mn = m+n

Rearrange:

mn - m = n

→

m(n-1) = n

Solve for

m

m = \frac{n}{n-1}

(provided

n \neq 1

, and

m,n > 0

Answer:

Option C:

\frac{n}{n-1}

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