Concept:Compare the values of x=10log35 and y=log1725 using logarithm properties and approximate magnitudes.Explanation:First, simplify y: y=log1725=log17(52)=2log175.Now, x=10log35. Since log35 is between 1 and 2 (because 31=3, 32=9), we have x between 10 and 20.The value log175 is less than 1 (since 171=17>5), so y=2log175 is less than 2.Thus x>10 and y<2, clearly x>y.Alternatively, using change of base: x/y=(10log35)/(2log175)=5⋅(log35/log175)=5log317>5⋅2=10, so x>y.Answer:x>y (Option C).