Concept:Use the property loga−logb=logba and equate arguments.Explanation:Given: log(2a−3b)=loga−logb.Using log property: loga−logb=logba.So, log(2a−3b)=logba.Since logs are equal, 2a−3b=ba.Multiply both sides by b: b(2a−3b)=a ⇒ 2ab−3b2=a.Rearrange: 2ab−a=3b2 ⇒ a(2b−1)=3b2.Thus, a=2b−13b2.Answer:a=2b−13b2, which matches option A.