Management Aptitude Test 2014 Paper

(a) Let Aditi pay for the article = ₹ xShe spent ₹ 110 on its repair, so its total cost = ₹ (x + 110)Now, she sold it to Samir at a profit of 20%.So, sale price = {x + 110) + (x + 110) $\times \frac{20}{100}$= (x+110)+ $\frac{x+110}{5}$=$\frac{5x+550+x+110}{5} = \text{Rs.} \left(\frac{6x+660}{5}\right)$Now, Samir sold it to Vikas at a loss of 10%.So, sale price =$\left(\frac{6x+660}{5}\right) - \frac{6x+660}{5} \times \frac{10}{100}$= $\left(\frac{6x+660}{5}\right) - \frac{6x+660}{50}$= $\frac{6x+6600-6x-660}{50}$= ₹ $\frac{54x+5940}{50}$Now, finally Vikas sold it for ₹ 1188, at a profit of 10% So, sale price = $\frac{54x+5940}{50}$ + $\frac{54x+5940}{50} \times \frac{10}{100}$⇒ 1188 = $\frac{54x+5940}{50}$+$\frac{54x+5940}{500}$⇒1188= $\frac{540x+59400+54x+5940}{500}$⇒$\frac{594x+65340}{500}$ =1188⇒ 148.5x + 16335 = 148500⇒148.5x = 132165⇒x = $\frac{12165}{148.5}$⇒x = ₹ 890So, Aditi bought the article for ₹ 890.