Management Aptitude Test Dec 2013 Paper

(a ) Let amount of solution be 100 ml
∵ Amount of water = 40 ml
∴ Amount of milk = 60 ml
Let amount of solution replaced be x ml.
New solution that is added has 81% milk and 19% water.
∴ Amount of water in new solution obtained = 26% = 26 ml
40 -

40

100

x+

19

100

x = 26
⇒40 - 26 =

21

00

x
⇒ 14 =

21

00

x
⇒ x =

14

21

× 100 =

2

3

× 100
∴ Quantity of milk replaced =

2 3 ×100

100

=

2

3