(2) Let charge for the distance = ₹ x and fixed charge = ₹ y Then, according to given condition, lOx + y = 85 ...(i) 15x + y = 120 ...(ii) Solving these Eqs. (i) and (ii), we get x = ₹ 7 ,y = ₹15 Hence, fare for journey of 25 km = ₹ (25x + y ) = ₹ (25 x 7 + 15) = ₹ 190