Management Aptitude Test Sep 2013 Paper

(e) Amount o f water in 1st vessel =

1

5

x 100 = 20 L
∴ Amount of milk in 1st vessel =

4

5

x 100 = 80 L
Similarly, amount of water in 2nd vessel =

3

5

x 100 = 60 L
Amount of milk in 2nd vessel =

2

5

x 100 = 40 L
Amount of water in 3rd vessel =

3

7

×100=

300

7

Amount of milk in 3rd vessel =

4

7

×100=

400

7

∴ Required ratio =

20+60+ 300 7

80+40+ 400 7

=

140+420+300 7

560+280+400 7

=

860

1240

=

43

62