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Manipal Entrance Test 2013 Chemistry Paper

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Question : 7

Total: 60

Following method of extracting Zn is based on thermodynamics
A:2‌ZnS+3O2 –––––🢖2‌ZnO+2SO2
B:ZnO+C –––––🢖‌Zn+CO
If ΔG°f (standard free energies of formation , in kJmol‌−1 ) of ZnS = - 205.4,
ZnO = -318.0, SO2 = -300.4 and of CO = -137.3
Free energy changes of the above reaction A and B (respectively) will be

-826.4 kJ, +180.9 k J
+826.4 kJ, -180.9 k J
-826.4 kJ, -180.9 k j
+826.4 kJ, +180.9 k J

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