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Manipal Entrance Test 2013 Math Paper
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© examsnet.com
Question : 51
Total: 80
The value of
tan
{
1
2
cos
−
1
(
√
5
3
)
}
is
3
+
√
5
2
3
+
√
5
1
2
(
3
+
√
5
)
None of these
Validate
Solution:
cos
−
1
(
√
5
3
)
=
α
cos
α
=
√
3
2
0
<
α
<
π
2
tan
α
2
=
√
1
−
cos
α
1
+
cos
α
=
√
1
−
√
5
3
1
+
√
5
3
=
√
3
−
√
5
3
+
√
5
=
√
(
3
−
√
5
)
2
9
−
5
√
(
3
)
2
+
(
√
5
)
2
−
2
(
3
)
(
√
5
)
9
−
5
=
(
√
9
+
5
−
6
√
5
4
)
=
√
14
−
6
√
5
4
=
√
(
7
−
3
√
5
)
2
© examsnet.com
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