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Manipal Entrance Test 2015 Math Paper
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© examsnet.com
Question : 14
Total: 70
The proposition
(
p
→
~
p
)
⋀
(
~
p
→
p
)
is
a tautology
a contradiction
neither tautology nor contradiction
both tautology and contradiction
Validate
Solution:
The truth table of
(
p
→
~
p
)
⋀
(
~
p
→
p
)
is as follows:
p
~
p
p
→
~
p
~
p
→
p
(
p
→
~
p
)
⋀
(
~
p
→
p
)
T
F
F
T
F
F
T
T
F
F
Clearly, last column of the above truth table contains F only. So, the given statement is a contradiction.
© examsnet.com
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