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Manipal Entrance Test 2016 Physics Paper
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© examsnet.com
Question : 21
Total: 50
Two bar magnets having same geometry with magnetic moments
m
and
2
m
,
are firstly placed in such a way that their similar poles one are on same side. Then, its time period of oscillation is
T
1
. Now, the polarity of the one of the magnet is reversed.Then, time period of oscillation is
T
2
, then
T
1
<
T
2
T
1
=
T
2
T
1
>
T
2
T
2
=
∞
Validate
Solution:
When similar poles are on same side time period of oscillation
T
1
is given by
T
1
=
2
π
√
I
1
+
I
2
(
m
1
+
m
2
)
B
H
m
1
=
2
m
,
m
2
=
m
T
1
=
2
π
√
I
1
+
I
2
(
3
m
)
B
H
...(i)
When the polarity of magnet is reversed, time period of oscillation
T
2
is given by
T
2
=
2
π
√
I
1
+
I
2
(
m
1
−
m
2
)
B
H
T
2
=
2
π
√
I
1
+
I
2
m
B
H
...(ii)
On comparing Eqs. (i) and (ii), we get
T
2
>
T
1
or
T
1
<
T
2
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