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Manipal Entrance Test 2017 Chemistry Paper
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© examsnet.com
Question : 2
Total: 50
The mass of oxygen that would be required to produce enough CO which completely reduces
1.6
kg
Fe
2
O
3
(at. mass
Fe
=
56
)
, is
240
g
480
g
720
g
960
g
Validate
Solution:
3
C
+
3
2
O
2
→
3
CO
Fe
2
O
3
+
3
CO
→
2
Fe
+
3
CO
2
1 mole of
Fe
2
O
3
≡
3
mole
of
CO
≡
3
2
mole
of
O
2
∵
160
g
of
Fe
2
O
3
require
O
2
=
3
2
×
32
=
48
g
∴
1.60
kg
of
Fe
2
O
3
will require
O
2
=
480
g
© examsnet.com
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