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Manipal Entrance Test 2017 Physics Paper
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© examsnet.com
Question : 39
Total: 50
When an equilateral prism of refractive index
√
2
produces minimum deviation the angle of incidence at the first face must be
30°
42°
60°
75°
Validate
Solution:
The angle of minimum deviation is given by
δ
m
=
(
n
−
1
)
A
δ
m
=
(
√
2
−
1
)
60
Angle of incidence,
i
=
A
+
δ
m
2
i
=
60
+
(
√
2
−
1
)
60
2
i
=
60
√
2
2
=
30
√
2
=
42
°
© examsnet.com
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