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Manipal Entrance Test 2017 Physics Paper
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© examsnet.com
Question : 48
Total: 50
First diffraction minima due to a single slit of width
10
−
4
cm
is at
θ
=
30
°
. Then wavelength of the light used is
4000
Å
5000
Å
6000
Å
6250
Å
Validate
Solution:
a
sin
θ
=
1
×
λ
λ
=
a
sin
θ
=
10
−
4
×
1
2
=
10
×
10
−
5
2
=
5
×
10
−
5
cm
=
5000
Å
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