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Manipal Entrance Test 2018 Math Paper
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© examsnet.com
Question : 54
Total: 70
If A + B + C = π, then
|
sin
(
A
+
B
+
C
)
sin
B
cos
C
−
sin
B
0
tan
A
cos
(
A
+
B
)
−
tan
A
0
|
is equal to
sin A
sin A cos B
0
None of these
Validate
Solution:
In a triangle ABC,
A + B + C = π
⇒
sin
(
A
+
B
+
C
)
=
0
,
cos
(
A
+
B
)
=
−
cos
C
∴
|
sin
(
A
+
B
+
C
)
sin
B
cos
C
−
sin
B
0
tan
A
cos
(
A
+
B
)
−
tan
A
0
|
=
|
0
sin
B
cos
C
−
sin
B
0
tan
A
−
cos
C
−
tan
A
0
|
=
0
(∵ It is the determinant of a skew symmetric matrix of odd order.)
© examsnet.com
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