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Manipal Entrance Test 2018 Physics Paper
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© examsnet.com
Question : 29
Total: 50
The light ray is incident at angle of
60
°
on a prism of angle
45
°
.
When the light rays falls on the other surface at
90
°
, the refractive index of the material of prism
mu
and the angle of deviation
δ
are given by
µ
=
√
2
,
δ
=
30
°
µ
=
1.5
,
δ
=
15
°
µ
=
√
3
2
,
δ
=
30
°
µ
=
√
3
2
,
δ
=
15
°
Validate
Solution:
From the problem it is clear that
∠
e
=
∠
r
2
=
0
From
A
=
r
1
+
r
2
⇒
r
1
=
A
=
45
°
∴
µ
=
sin
i
sin
r
1
=
sin
60
°
sin
45
°
=
√
3
2
Also, from
i
+
e
=
A
+
δ
⇒
60
+
0
=
45
+
δ
⇒
δ
=
15
°
© examsnet.com
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