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Manipal Entrance Test 2019 Chemistry Paper
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© examsnet.com
Question : 4
Total: 50
The ratio of rate of diffusion of
SO
2
(M = 64) and oxygen (M = 32) is
1
:
1
2
:
1
1
:
2
1
:
1.414
Validate
Solution:
Molecular weight of
S
O
2
(
M
1
)
=
64
Molecular weight of
O
2
(
M
2
)
=
32
According to Graham's law of diffusion
r
1
r
2
=
√
M
2
M
1
=
√
32
64
=
1
√
2
or
=
1
1.414
© examsnet.com
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