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Manipal Entrance Test 2019 Math Paper
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© examsnet.com
Question : 66
Total: 70
The approximate value of
5
∫
1
x
2
d
x
using trapezoidal rule with
n
=
4
is
41
41.5
41.75
42
Validate
Solution:
5
∫
1
x
2
d
x
=
4
4
[
1
2
f
(
1
)
+
f
(
2
)
+
f
(
3
)
+
f
(
4
)
+
1
2
f
(
5
)
]
=
1
2
[
x
2
F
(
x
2
)
−
∫
F
(
x
2
)
d
(
x
2
)
]
=
[
1
2
+
4
+
9
+
16
+
25
2
]
=
42
[using
f
(
x
)
=
x
2
]
© examsnet.com
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