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Manipal Entrance Test 2019 Physics Paper
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© examsnet.com
Question : 49
Total: 50
A physicist works in a laboratory where the magnetic field is 2 T. She wears a necklace enclosing area
0.01
m
2
in such a way that the plane of the necklace is normal to the field and is having a resistance,
R
=
0.01
Ω
. Because of power failure, the field decays to
1
T
in time
10
−
3
s
. Then what is the total heat produced in her necklace?
10 J
20 J
30 J
40 J
Validate
Solution:
Induced emf
E
=
−
Δ
ϕ
Δ
t
=
−
A
Δ
B
Δ
t
=
−
0.01
×
1
−
2
10
−
3
=
0.01
10
−
3
= 10 V
∴ Heat produced,
H
=
E
2
R
t
=
10
2
0.01
×
10
−
3
=
10
J
© examsnet.com
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