Let A={pmatrix} 2 & 3 \\ 4 & 5 {pmatrix} ; B={pmatrix} 1 & 5 \\ 6 & 7 {pmatrix} then the value A-3B

Correct Answer is : (−1−12−14−16){pmatrix} -1 & -12 \\ -14 & -16 {pmatrix}(−1−14−12−16)

{pmatrix} -1 & -12 \\ -14 & -16 {pmatrix}

{pmatrix} 1 & -12 \\ -14 & 16 {pmatrix}

{pmatrix} -1 & 12 \\ -14 & 16 {pmatrix}

{pmatrix} 1 & 12 \\ 14 & 16 {pmatrix}

Correct Answer is : (−1−12−14−16){pmatrix} -1 & -12 \\ -14 & -16 {pmatrix}(−1−14−12−16)

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Question : 34 of 36

Marks: +1, -0

Let

A=\begin{pmatrix} 2 & 3 \\ 4 & 5 \end{pmatrix} ; B=\begin{pmatrix} 1 & 5 \\ 6 & 7 \end{pmatrix}

A-3B

Solution:

Concept:

Matrix subtraction and scalar multiplication: subtract corresponding entries after multiplying matrix by scalar.

Explanation:

Given

A = \begin{pmatrix} 2 & 3 \\ 4 & 5 \end{pmatrix}

and

B = \begin{pmatrix} 1 & 5 \\ 6 & 7 \end{pmatrix}

First compute

3B = 3 \times \begin{pmatrix} 1 & 5 \\ 6 & 7 \end{pmatrix} = \begin{pmatrix} 3 & 15 \\ 18 & 21 \end{pmatrix}

Then

A - 3B = \begin{pmatrix} 2-3 & 3-15 \\ 4-18 & 5-21 \end{pmatrix} = \begin{pmatrix} -1 & -12 \\ -14 & -16 \end{pmatrix}

Answer:

\begin{pmatrix} -1 & -12 \\ -14 & -16 \end{pmatrix}

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