(b) We have, dxdy=tan(xy)+(xy) ..........(i) Since, it is homogeneous differential equation After putting, y=Vx, we get dxdy=V+xdxdVV+xdxdV = tanV+V [From (i) ] ⇒ xdxdV=tanV ⇒ tanV1dV=x1dx After integrating on both sides, we get ∫tanV1dV=∫x1dx ⇒ ∫cot VdV = logx + logc ⇒ log sin V = log(xc)⇒ sin v = xcHence, sin (xy) = xc