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MHT CET 2018 Math Solved Paper
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© examsnet.com
Question : 31
Total: 50
π
4
∫
0
x
.
sec
2
x
d
x
=
π
4
+
log
√
2
π
4
−
log
√
2
1
+
log
√
2
1
−
1
2
log2
Validate
Solution:
(b)
π
4
∫
0
x
sec
2
x
d
x
=
[
x
∫
sec
2
x
d
x
]
0
π
4
-
π
4
∫
0
[
d
d
x
x
∫
sec
2
x
d
x
]
d
x
=
[
x
⋅
tan
x
]
0
π
4
-
π
4
∫
0
[
tan
x
]
d
x
=
[
x
⋅
tan
x
]
0
π
4
-
[
log
|
sec
x
|
]
0
π
4
=
[
π
4
−
0
]
-
[
log
|
sec
π
4
|
-
log
|
sec
0
|
]
=
π
4
−
[
log
√
2
−
log
1
]
=
π
4
−
log
√
2
© examsnet.com
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