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MHT CET 2020 Physics Solved Paper
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© examsnet.com
Question : 4
Total: 50
Two simple harmonic motions are represented by the equations
y
1
=
0.1
sin
(
100
π
t
+
π
3
)
and
y
1
=
0.1
cos
π
t
The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is
π
3
−
π
6
π
6
−
π
3
Validate
Solution:
v
1
=
d
y
1
d
t
=
0.1
×
100
π
cos
(
100
π
t
+
π
3
)
v
2
=
d
y
2
d
t
=
−
0.1
π
sin
π
t
=
0.1
π
cos
(
π
t
+
π
2
)
∴
Phase diff.
=
φ
1
−
φ
2
=
π
3
−
π
2
=
2
π
−
3
π
6
=
−
π
6
© examsnet.com
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