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MHT CET 2021 Math Solved Paper
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© examsnet.com
Question : 49
Total: 100
The area in the positive quadrant enclosed by the circles
x
2
+
y
2
=
4
, the line
x
=
y
√
3
and
X
-axis is
π
2
π
4
π
3
π
Validate
Solution:
The intersection points of curves
x
2
+
y
2
=
4
and
y
=
x
√
3
are
(
0
,
0
)
and
P
(
√
3
,
1
)
.
∴
Area of
△
O
P
M
=
1
2
×
√
3
×
1
=
√
3
2
and area of curve
M
P
Q
=
∫
√
3
2
√
4
−
x
2
d
x
=
[
x
2
√
4
−
x
2
+
4
2
sin
−
1
(
x
2
)
]
√
3
2
=
[
0
+
2
(
π
2
)
−
(
√
3
2
+
2
×
π
3
)
]
=
(
π
3
−
√
3
2
)
]
© examsnet.com
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