MHTCET 11 Apr 2026 Shift 1 Paper

Concept:For a series LCR circuit, only the resistor dissipates average power while the inductor and capacitor store and return energy.Explanation:Given, $X_L = 100\ \Omega$, $X_C = 50\ \Omega$, $R = 50\ \Omega$, and the AC source voltage is $V = 10\ \text{V}$.The net reactance of the series circuit is$$X = X_L - X_C = 100 - 50 = 50\ \Omega$$The impedance of the circuit is$$Z = \sqrt{R^2 + X^2} = \sqrt{50^2 + 50^2} = \sqrt{5000} = 50\sqrt{2}\ \Omega$$Therefore, the rms current in the circuit is$$I = \frac{V}{Z} = \frac{10}{50\sqrt{2}} = \frac{1}{5\sqrt{2}}\ \text{A}$$Average power dissipated by the circuit is given by$$P = I^2 R = \left(\frac{1}{5\sqrt{2}}\right)^2 \times 50 = \frac{1}{50} \times 50 = 1\ \text{W}$$Hence, the average power dissipated is 1 W.Answer:$1\ \text{W}$, which is option A.